MATH AGES

                                               PROBLEM   ON AGES  

  This is one  of the simplest question type in which age are asked ,the age may be present age,  earlier age or after age.

                         There is no theory involve here.

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                                       QUESTION

QUESTION 1:    3 YEAR EARLIER THE FATER WAS 7 TIMES AS OLD AS HIS SON. 3 YEAR HENCE(AFTER) THE FATHER AGE   WOULD BE 4 TIMES THAT OF HIS SON .THEN FIND WHAT IS PRESENT AGE OF FATHER AND SON ?.

Solotion :

       L et the present age of father and son  is x,y year.

           According to question

     3 year earlier:             (x-3)  = 7*(y-3)

                                            x-7y=-18         (1)

 3 year after  :          (x+3) =4(y+3)

                                    x-4y=9            (2)

               subtract equation (1)  from equation (2)

                          3y=27

                            Y=9

  Now          x=9+4y=45         [from (2)]

                        There fore father age  is 45 year and son age is 9 year.

QUESTION 2:  THE SUM OF PRESENT AGE OF  FATHER AND SON  IS 56 YEAR. 4 YAER HENCE SON AGE WILL BE 1/3 OF THAT FATHER .WHAT  ARE  PRESENT AGE OF FATHER AND SON  ?.                

Solution :    Let  present age of father and son is x,y.

                    Then     x+y=56           (1)

                      Now       (x+4  )/3 =y+4      

                                      x+4=3y+12

                                      x-3y=8        (2)

 subtract (2)  from (1)

   4y=48

   Y=12

Now x =8+3y=8+36=44

   Therefore father , son age is 44,12 year respectively.